Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    n %= 8;
    for (int i = 0; i < n; ++i) {
        if (reg & 1) {
            reg >>= 1;
            reg |= 0x80000000;
        } else {
            reg >>= 1;
        }
    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach