Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    n%=32;
    /*if(n==0){
        return reg;
    }*/
    uint32_t reg_new= ((reg&((1U << n)-1))<<(32-n));
    //printf("%u \n",reg_new);
    reg= (reg>>n)| reg_new;
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach