Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    for(int i=0; i < n; i++){
        // get the rightmost bit
        uint32_t right_bit = reg & 1;

        // shift right 
        reg >>= 1;

        // place the rightmost bit at the left most bit
        reg |= (right_bit << 31);

    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach