Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    //Rotate right by n bits in circular
    //1. Bitshift right by n bits (000111...)
    //2. Bitshift left by (size of reg - n) bits to put "lost bits" at back (1110000)
    //3. Combine both
    
    n%=32; //Sets a limit so n cannot be greater than 32 (size of reg) (loops round if > 32)
    return (reg >> n) | (reg << 32-n);
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

2147483648 1

Expected Output

1073741824