Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint32_t j=n;
    uint32_t value=0;
    for(uint32_t i=0; i<n; i++)
    {   
        value=reg&1;
        // printf("%d\n",value);
        reg=reg>>1;
        // printf("%d\n",reg);
        reg=reg|(value<<(31));
        // printf("%d\n",reg);
        // return reg;
        // j=j-i;

        
        
    }
    
    
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach