Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, int n) {
    // Your code here
    uint32_t result = (reg >> n) | (reg << (32 - n));
    return result;
}

int main() {
    uint32_t reg;
    int pos;
    scanf("%u %d", &reg, &pos);
    printf("%u", rotate_right(reg, pos));
    return 0;
}

Solving Approach