Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
     if(n==0)return reg;
        uint32_t right=(reg>>n)&0xFFFFFFFF;
        uint32_t wrap= (reg<<(32-n));
        uint32_t result=((right|wrap)&0xFFFFFFFF); 
        return result;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach