Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
     for(int i=0;i<n;i++){
        int val = reg>>0&1;
        reg = reg>>1;
        reg = reg | val<<31;
        
    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach

Step 1:- iterating the for loop n times.

 for(int i=0;i<n;i++) {

Step 2:- fetching the value at 0 position from reg. 

        int val = reg>>0&1;

Step 3:- rotate right shift once in loop

        reg = reg>>1;

Step 4:- inserting the fetched value in 31 position in reg

        reg = reg | val<<31;

    }

Step 5:-  return the reg

    return reg;