Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    uint32_t res;
    uint32_t bit;
    int i,pos=n; 
    res=reg>>n;
    for(i=0;i<n;i++){
        bit=(reg>>i)&1;
        res|=bit<<(32-pos);
        pos--;}

    res&=0xffffffff;

    return res;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach