Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint32_t new_reg = reg;
    uint32_t lsb = 0;
    while(n!=0){
        lsb = (new_reg & 0x1);

        new_reg = new_reg >> 1;

        new_reg |= (lsb << 31); 

        n--;

    }   

    return new_reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach