Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint32_t mask =0; 
    uint32_t temp = reg; 
    for (int i=0; i < n; i++){
        mask |=  (temp&1U) << i; 
        temp >>= 1; 
    }
    // printBinary(mask); 
    reg >>= n; 
    // printBinary(reg); 
    mask <<= 32-n; 
    // printBinary(mask);
    reg = reg|mask; 
    // printBinary(reg);


    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach