Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
  n = n%32;
  return (reg<<32-n)|(reg>>n);

}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}
/*reg         0000 1111 0000 1111 0000 1111 0000 1111

reg<<32-n   0000 1111 0000 1111 0000 1111 0000 0000
reg>>n      0000 0000 0000 1111 0000 1111 0000 1111

            0000 1111 0000 1111 0000 1111 0000 1111*/

Solving Approach