Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    n = n % 32;
    uint32_t mask = (1U << 31);
    for(int i=0; i<n; i++)
    {
        if(reg & 1U)
        {
            reg >>= 1;
            reg |= mask;
        }
        else
        {
            reg >>=1;
        }
    }

    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach