Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint32_t reg1=0;
    n=n%32;
    if (n==0)
    return reg;
    //Step 1: Extract the bit to be rotated right
    for (int i=0;i<n;i++){
         reg1 |= ((reg >> i) & 1)<<(32-(n-i));
    }
    //Step 2: Consolidation
    reg=(uint32_t)((reg>>n) | reg1 );
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach