Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint32_t result;
    for(int i=0;i<32;i++){
        if(reg & (1<<i)){
            if((i-n)>= 0){
                result |= (1<<(i-n));
            } else{
                result |= (1<<((i-n)+32));
            }
        }
    }
    return result;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach