Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    uint32_t a=0,b=0;
    uint8_t c=0;
    int d=0;
    for(int i=0;i<n;i++){
        a=1&(reg>>i);
        b=b|(a<<c);
        c++;
    }
    reg=(reg>>n)|(b<<(32-n));
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

2147483648 1

Expected Output

1073741824