Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    
    while(n!=0){
        bool LSB = reg & 1U;
        reg >>= 1;
        if(LSB) reg |= 0x80000000;
        n--;
    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

2147483648 1

Expected Output

1073741824