#include <stdio.h>
int find_pattern(int *mem, int n) {
// Write your pointer-based logic here
int *p = mem;
int idx = 0;
// we can check while idx <= n-3 so p+2 stays inside the buffer
while (idx <= n - 3) {
int a = *p;
int b = *(p + 1);
int c = *(p + 2);
// use difference checks (safer vs potential overflow than a+1 comparisons)
if ((b - a == 1) && (c - b == 1)) {
return idx;
}
p++; // pointer walk to next element
idx++; // keep track of the index to return
}
return -1;
}
int main() {
int n, arr[100];
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = find_pattern(arr, n);
printf("%d", res);
return 0;
}
Input
8 2 4 5 6 9 11 12 14
Expected Output
1