#include <stdio.h>
int find_pattern(int *mem, int n) {
// Write your pointer-based logic here
if(n < 3)
return -1;
for(int i = 0; i < n - 2; i++){
int current = *(mem + i);
int next1 = *(mem + i + 1);
int next2 = *(mem + i + 2);
if((next1 == current + 1) &&(next2 == current + 2))
return i;
}
return -1;
}
int main() {
int n, arr[100];
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = find_pattern(arr, n);
printf("%d", res);
return 0;
}