#include <stdio.h>
int find_pattern(int *arr, int n) {
// Write your pointer-based logic here
int* p1 = arr, *p2 = arr + 1, *p3 = arr + 2;
for(int i = 0; i <= n - 3; i++)
{
if(*p1 + 1 == *p2 && *p2 + 1 == *p3)
return i;
*p1++;
*p2++;
*p3++;
}
return -1;
}
int main() {
int n, arr[100];
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = find_pattern(arr, n);
printf("%d", res);
return 0;
}