#include <stdio.h> int find_pattern(int *mem, int n) { // Write your pointer-based logic here int first_element, second_element, third_element; for(int i=0; i<n; i++){ first_element = *mem; second_element = *(mem+1); third_element = *(mem+2); if(second_element==first_element+1 && third_element==second_element+1){ return i; } mem++; } return -1; } int main() { int n, arr[100]; scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &arr[i]); } int res = find_pattern(arr, n); printf("%d", res); return 0; }
Test Cases
Test Results
Input
8 2 4 5 6 9 11 12 14
Expected Output
1