#include <stdio.h> int find_pattern(int *mem, int n) { // Write your pointer-based logic here int *tmp = mem; while(tmp < &mem[n-2]) { if((*tmp+1 == *(tmp+1)) & (*(tmp+1)+1 == *(tmp+2))) { return tmp - mem; } tmp+=1; } return -1; } int main() { int n, arr[100]; scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &arr[i]); } int res = find_pattern(arr, n); printf("%d", res); return 0; }
Test Cases
Test Results
Input
8 2 4 5 6 9 11 12 14
Expected Output
1