#include <stdio.h>
int find_pattern(int *mem, int n) {
// Write your pointer-based logic here
if(!mem || n <= 0) return -1;
int* p1 = mem;
int* p2 = mem + 2;
for(int i = 0; i < n - 2; i++) {
if((*p1 == *(p1 + 1) - 1) && (*(p1 + 1) == *(p1 + 2) - 1)) return i;
p1++;
p2++;
}
return -1;
}
int main() {
int n, arr[100];
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = find_pattern(arr, n);
printf("%d", res);
return 0;
}