#include <stdio.h>
int find_pattern(int *mem, int n)
{
// Write your pointer-based logic here
int *p = mem; // pointer walking
for (int i = 0; i <= n - 3; i++) {
int *a = p + i; // first element
int *b = p + i + 1; // second element
int *c = p + i + 2; // third element
if ((*a + 1 == *b) && (*b + 1 == *c))
{
return i; // starting index of pattern
}
}
return -1;
}
int main() {
int n, arr[100];
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int res = find_pattern(arr, n);
printf("%d", res);
return 0;
}