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Set or Clear a Specific Bit in a Register

Code

#include <stdio.h>

unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    // Write your code here
    // 10 = 00001010
    if(mode==1)
        return reg|=(1<<pos);
    else if(mode==0)
        return reg&=~(1<<pos);
}

int main() {
    unsigned char reg;
    int pos, mode;
    scanf("%hhu %d %d", &reg, &pos, &mode);
    printf("%d", modifyBit(reg, pos, mode));
    return 0;
}

Solving Approach

 

  • Bitwise Operations Used
    • Set bit: reg | (1 << pos)
      • Shifts 1 to the left by pos places and ORs it with reg.
      • This ensures the bit at pos becomes 1.
    • Clear bit: reg & ~(1 << pos)
      • Shifts 1 to the left by pos places, inverts it with ~, and ANDs with reg.
      • This ensures the bit at pos becomes 0.
  • Steps
    • Take input values: reg, pos, and mode.
    • If mode = 1, set the bit at position pos.
    • If mode = 0, clear the bit at position pos.
    • Return the modified value.

 

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Input

10 3 1

Expected Output

10