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Set or Clear a Specific Bit in a Register

Code

#include <stdio.h>

unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    if(mode==1)
    {
        reg=reg|(1<<pos);
    }
    else
    {
        reg=reg&~(1<<pos);
    }
    return reg;
}

int main() {
    unsigned char reg;
    int pos, mode;
    scanf("%hhu %d %d", &reg, &pos, &mode);
    printf("%d", modifyBit(reg, pos, mode));
    return 0;
}

Solving Approach

 

just passing the values of registers , bit position and operative mode as an arguments of function modifyBit

Then by using conditional statements (if and else) to choose the mode

IF condition:

if the value of mode is equal to one , then we need to set the specified bit that we passed in function by 

i) Left shift the binary number 1 to Pos value 

ii)doing bitwise OR between reg and shifted value

Else condition:

i) Left shift the binary number 1 to Pos value 

ii)perform bitwise NOT to flip the bits

iii)Then perform bitwise AND between reg and flipped bits

 

Then return the value of reg

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Input

10 3 1

Expected Output

10