Set or Clear a Specific Bit in a Register

Code
#include <stdio.h>

unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    // Write your code here
    if(mode)
    reg = reg | (1<<pos);
    else
    reg = reg & ~(1<<pos);
    
    //and you guys try with this single line logic
	//reg = mode ? (reg | (1<<pos)) : (reg & ~(1<<pos));
    
    return reg; 
}

int main() {
    unsigned char reg;
    int pos, mode;
    scanf("%hhu %d %d", &reg, &pos, &mode);
    printf("%d", modifyBit(reg, pos, mode));
    return 0;
}
Solving Approach
unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    // Write your code here
    if(mode)
    reg = reg | (1<<pos);
    else
    reg = reg & ~(1<<pos);
    
    return reg; 
}

unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    // Write your code here
    if(mode)
    reg = reg | (1<<pos);
    else
    reg = reg & ~(1<<pos);
    
    return reg; 
}

Step 1.

if(mode)
    reg = reg | (1<<pos);

if mode is true(1);

reg = reg | (1<<pos)

(1<<pos) 1 is left shifting to desired position. without effecting other bits. 

Step 2.

else
    reg = reg & ~(1<<pos);

~(1<<pos) in this step 1 left shifting to desired position. and complementing the result.

reg & ~(1<<pos). and (&) operation between reg and result of (~(1<<pos);

Step-3

and you guys try with this single line logic

reg = mode ? (reg | (1<<pos)) : (reg & ~(1<<pos));