Set or Clear a Specific Bit in a Register

Code

#include <stdio.h>

unsigned char modifyBit(unsigned char reg, int pos, int mode) {
    // Write your code here
    if(mode == 1)
    {
        reg |= (1 << pos);
    }
    else
    {
        reg &= ~(1 << pos);
    }
    return reg;

}

int main() {
    unsigned char reg;
    int pos, mode;
    scanf("%hhu %d %d", &reg, &pos, &mode);
    printf("%d", modifyBit(reg, pos, mode));
    return 0;
}

Solving Approach

Based on the user mode (1 set or 0 clear), the bit is shifted left to the specified position pos and a AND operation is performed with the negate of the bit post in case of clear and OR operation is performed in case of set.