Set Specific Bits in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t set_bits(uint32_t reg, uint8_t pos, uint8_t len) {
    // Your code here
    uint32_t mask = ((1<<len)-1);
    return reg|(mask<<pos);
}

int main() {
    uint32_t reg;
    uint8_t pos, len;
    scanf("%u %hhu %hhu", &reg, &pos, &len);
    printf("%u", set_bits(reg, pos, len));
    return 0;
}

Solving Approach

As we want 1 of certain length side by side. remember that 2^3 - 1 gives 3 ones.

using the above idea we make that ones side by side named as mask.
And, this mask is again shifted by position to set bits in register