Set the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t set_bit(uint8_t reg, uint8_t pos) {
    uint8_t tem = ( 1 << pos);
    for (uint8_t i = pos ; i < 8 ; i ++) {
        if ((reg & tem) == 00000000) {
            reg |= (1 << i);
            break;
        }
    }
    return reg;
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);  // Accept register value and position
    uint8_t result = set_bit(reg, pos);
    printf("%u", result);         // Output the result as an integer
    return 0;
}

Solving Approach