Set the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t set_bit(uint8_t reg, uint8_t pos) {
    // Your code here
    return reg | (1<<pos);
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);  // Accept register value and position
    uint8_t result = set_bit(reg, pos);
    printf("%u", result);         // Output the result as an integer
    return 0;
}

Solving Approach
 

✅ Set Bit in 8-bit Register — Small & Compact Approach

1️⃣ Create mask for the target bit

1 << pos

This generates a value where only the pos bit is 1.

2️⃣ Use OR to set the bit

reg | (1 << pos)

Why OR?

• 0 | 1 = 1 → sets the bit
• 1 | 1 = 1 → remains 1
• Other bits unchanged

💡 Final One-Line Logic

return reg | (1 << pos);

✔ Sets only the specified bit
✔ Does not affect other bits
✔ Constant time
✔ Embedded-friendly