Simulate memcpy function Using Pointer Walk

Code

#include <stdio.h>

void simulate_memcpy(int *dest, int *src, int n) {
    // Your logic here
    // Typecast src and dest addresses to (char *) 
int *csrc = src; 
int *cdest = dest; 

// Copy contents of src[] to dest[] 
for (int i=0; i<n; i++) {
    *cdest = *csrc; 
    cdest++;
    csrc++;}
} 



int main() {
    int n;
    scanf("%d", &n);

    int src[100], dest[100];

    for (int i = 0; i < n; i++) {
        scanf("%d", &src[i]);
    }

    simulate_memcpy(dest, src, n);

    for (int i = 0; i < n; i++) {
        printf("%d", dest[i]);
        if(i < n-1){
           printf(" "); 
        }
    }

    return 0;
}

Solving Approach