58. Simulate memcpy function Using Pointer Walk

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
 
void simulate_memcpy(int *dest, int *src, int n){
    for(int i = 0; i < n; i++){
        *(dest + i )= *(src + i);
    }
}

int main(){
   int n, src[100], dest[100];
   scanf("%d", &n);

   for(int i = 0; i < n ; i++){
       scanf("%d", &src[i]);
   }

   simulate_memcpy(dest, src, n);

   for(int i = 0; i < n ; i++){
       printf("%d ", dest[i]);
   }
   return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote