Split a String Using Delimiter

Code

#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <string.h>

void split_string(const char *str, char delimiter, char tokens[10][20], uint8_t *count) 
{
    int i=0;
    int j=0;
    char *temp=(char *)malloc(100*sizeof(char));
    if(!temp)
    {
      printf("Memory allocation issue\n");
      exit(EXIT_FAILURE);
    }

    int k=0;


    while(str[i])
    {
        if(str[i+1]=='\0' || str[i]==delimiter) //once delimiter is found we need to terminate with null character to form proper string.
        {
            if(str[i+1]=='\0') //this is to take care of last token without miss.
              temp[j++]=str[i];
              
            temp[j]='\0';
            j=0;

            if(strlen(temp)>0) //this is just to handle edge cases like cmd1,,cmd2
            {
              while(temp[j])
              {
                tokens[k][j]=temp[j];
                j++;
              }
               tokens[k][j]=temp[j];
               j=0;
               k++;
            }
        }
        else //until we found delimiter we keep on storing into buffer.
          temp[j++]=str[i];

        i++;
    }

    *count=k;
}

int main() {
    char str[101];
    char delimiter;
    fgets(str, sizeof(str), stdin);
    scanf(" %c", &delimiter);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') { str[i] = '\0'; break; }
        i++;
    }

    char tokens[10][20];
    uint8_t count = 0;

    split_string(str, delimiter, tokens, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%s\n", tokens[i]);
    }

    return 0;
}

Solving Approach