Toggle the Bit in an 8-bit Register

Solving Approach

#include <stdio.h>
#include <stdint.h>

uint8_t toggle_bit(uint8_t reg, uint8_t pos) {
    // Your code here
    return reg ^ (1 << pos);
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);
    uint8_t result = toggle_bit(reg, pos);
    printf("%u", result);
    return 0;
}

Solving Approach

-> in XOR operation : 1 toggles the bits and 0 restores the original ones
-> create a mask by shifting 0x1 to the position you want to toggle and perform the XOR operation with the reg.