Toggle the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t toggle_bit(uint8_t reg, uint8_t pos) {
    // left shift 1 by <pos> bits and then XOR it with reg
    // 1 ^ 1 -> 0 ; 0 ^ 1 -> 1
    reg = reg ^ (1 << pos);
    return reg;
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);
    uint8_t result = toggle_bit(reg, pos);
    printf("%u", result);
    return 0;
}

Solving Approach