67. constexpr-ii

Question.5

A developer tries to debug a constexpr function by setting a breakpoint inside it:

constexpr uint32_t calc_timeout(uint32_t clk, uint32_t ms) {
   return (clk / 1000) * ms;  // Breakpoint here
}

constexpr uint32_t TIMEOUT = calc_timeout(72000000, 50);

Will the breakpoint be hit? (Select two choices)

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Yes -- the function runs normally and the debugger stops
No -- the function was evaluated at compile time; the code does not exist in the binary, so there is nothing to break on
Yes -- but only in debug builds
No -- but the runtime fallback version can be debugged

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