Bit Toggle

Code

#include <stdio.h>

int toggleFifthBit(int n) {
    // Write your code here

    return n = n ^ 1<<5;
}

int main() {
    int n;
    scanf("%d", &n);
    printf("%d", toggleFifthBit(n));
    return 0;
}

Solving Approach

✅ Bit Toggle – Small & Compact Solving Approach

1️⃣ Understand the target bit

• 0-based indexing
• 5th bit → position = 5
• Mask value = 1 << 5

2️⃣ Create the bit mask

1 << 5

This produces:

00100000  (decimal 32)

3️⃣ Use XOR to toggle

Rule:

• XOR with 1 → flips the bit
• XOR with 0 → unchanged

So:

N = N ^ (1 << 5);

4️⃣ Return/Print result

That’s it.

💡 Final Logic in One Line

result = N ^ (1 << 5);

✔ Simple
✔ No condition
✔ Constant time
✔ Embedded-safe