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Code

#include <stdio.h>

int toggleFifthBit(int n) {
    return n^0x20;
}

int main() {
    int n;
    scanf("%d", &n);
    printf("%d", toggleFifthBit(n));
    return 0;
}

Solving Approach

Here I have used 0x20 instead of 1<<5

Because answer for 1<<5 is 0x20

1--->binary-->00000001

1 << 5--->binary-->00100000

00100000---->hexadecimal--->0x20

 

 

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Input

8

Expected Output

40