CalibTable Constructor Copy

Question

Problem: CalibTable Constructor Copy. Solve this hands-on electronics task on EWskills.

Accepted Answer

#include 
using namespace std;

class CalibTable {
private:
    int size;
    int table[10];

public:
    CalibTable(int n, int arr[]) {
        if (n < 1) size = 1;
        else if (n > 10) size = 10;
        else size = n;

        for (int i = 0; i < size; i++) {
            table[i] = arr[i];
        }
    }

    int get(int index) {
        if (index < 0 || index >= size) return 0;
        return table[index];
    }

    void print() {
        for (int i = 0; i < size; i++) {
            cout << table[i];
            if (i + 1 < size) cout << " ";
        }
    }
};

int main() {
    int n;
    cin >> n;

    int arr[100];
    int countToRead = (n < 1 ? 1 : n);

    for (int i = 0; i < countToRead; i++) {
        cin >> arr[i];
    }

    CalibTable t(n, arr);
    t.print();

    return 0;
}

Explanation & Logic Summary:

The constructor clamps size to prevent buffer overflow
At least one calibration value is always read
Only valid elements are copied into the internal table
Bounds checking prevents invalid access
Behavior is deterministic and safe for embedded systems

Firmware Relevance & Real-World Context:

Calibration tables are commonly loaded from flash or EEPROM
Defensive size clamping prevents memory corruption
Ensuring at least one valid entry avoids boot-time faults
Mirrors safe initialization patterns used in embedded drivers

98. CalibTable Constructor Copy