#include <stdio.h> #include <stdint.h> const char* is_power_of_two(uint32_t n) { // Check if exactly one bit is set if (n > 0 && (n & (n - 1)) == 0) return "YES"; else return "NO"; } int main() { uint32_t n; scanf("%u", &n); const char* result = is_power_of_two(n); printf("%s", result); return 0; }
Test Cases
Test Results
Input
8
Expected Output
YES