Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    if (n!=0&&(n&(n-1))==0){
        return "YES";
    }
    else{
    // Your logic here
    return "NO";
}}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

if (n!=0&&(n&(n-1))==0){
        return "YES";}
    else{
    return "NO";}