Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    int temp=(n<<1);
    int temp1=n>>1;
    if(n==1){
        return "YES";
    }else if(n==0){
        return "NO";
    }
    else if( (temp-n==n) && (temp1+temp1==n)){
        return "YES";
    }
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach