Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    if(n==0)return "NO";
    uint32_t temp=1;
    bool found=false;
    for(int i=0;i<32;i++){
        if(temp==n){
            found=true;
            break;
        }
        temp<<=1;

    }
    return !found?"NO":"YES";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach