Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {


    uint32_t count = 0;
    // Count bits
    // Check that only one bit is set 
    for(int i=0; i < 32; i++){
        if((n >> i) & 1U){
            count++;
        }
    }
    if(count==1)
        return "YES";
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach