Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

const char* is_power_of_two(uint32_t n) {
    if((n%2==0 )|(n==1) && (n!=0) ){
       return "YES\n";
    }
    return "NO";
}
int main() {
    uint32_t n;
    scanf("%u", &n);
    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach