Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    // power of two if one bit is set
    if (!n) return "NO";
    if ((n & (n-1)) == 0) return "YES";
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach