Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    int counter = 0;
    for(int i=0;i<32;i++) {
        if(n & (1<<i)) counter++;
        if(counter  == 2) return "NO";
    }
    if(counter == 0) return "NO";
    return "YES";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach