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Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {

   uint32_t ex;
   int count = 0;

   int i;

   for(i=0;i<32;i++){
    ex = n & 0x00000001<<i;
    if(ex) count++;
    
   }
   if( count == 1 ) return "YES";
   else return"NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

 

 

 

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Input

8

Expected Output

YES