Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
   if(n & 1){
    while(n != 0){
        n = n >> 1;
        if(n & 1){
            return "NO";
        }
    }
   }
   else if(n == 0){
    return "NO";
   }
    return "YES";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

 

 

 

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Input

8

Expected Output

YES